![]() ![]() Looking at the console log it seems like the length of repeatLater is one plus the number of objects which is odd, the addition being proto. The JavaScript array findIndex () method returns the index of first element of the given array that satisfies the provided function condition. In this JavaScript tutorial were going to learn about the findIndex JavaScript Array Method and how it can be used to find and return the index of the. I suspect that the problem might be because there are objects/entries in the repeatLater array that do not have the ‘minTrial’ key. Occasionally I get thrown this error : TypeError: Cannot read property ‘minTrial’ of undefined repeatIdx = repeatLater.findIndex( x => x.minTrial <= trials.thisN ) The indexOf () method returns -1 if the value is not found. The findIndex () method does not execute the function for empty array elements. The indexOf () method returns the first index (position) of a specified value. The findIndex () method returns -1 if no match is found. The findIndex () method returns the index (position) of the first element that passes a test. After retrieving the trial, I delete that object from the array. The findIndex () method executes a function for each array element. ![]() Once the search index is found, we can access the search. repeatLater.push() Īt the beginning of the routine, I am using findIndex to search through repeatLater to find the index of the first instance where the my specifications are met, in this case I want the trial number to be at least the minTrial. The first approach would be to find the array index of the search object using Array.findIndex(). I created an array of objects (named repeatLater) where each object consists of specifications of a that I’d want to repeat after a number of trials. Hi all, This is more of a javascript question. ![]()
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